Zderivujte:
   $$
      y=x+\sqrt{x}+\sqrt[3]x.
   $$
   \reseni
   Uprav�me s��tance na tvar $x^n$ a pou�ijeme vzorec
   ${\left(x^n\right)}'=nx^{n-1}$.
   $$
      y'={\left(x + x^{1/2} + x^{1/3}\right)}'=1 + \frac12\cdot
      x^{-1/2} + \frac13\cdot x^{-2/3}=1 + \frac 1{2\sqrt x} +
      \frac 1{3\sqrt[3]{x^2}}.
   $$
